Enzyme Science Miscellaneous
- The degree of inhibition for non-competitive inhibition of an enzyme catalyzed reaction
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Non-competitive inhibitors are considered to be substances which when added to the enzyme alter the enzyme in a way that it cannot accept the substrate.
Correct Option: C
Non-competitive inhibitors are considered to be substances which when added to the enzyme alter the enzyme in a way that it cannot accept the substrate.
Direction: HMGCoA reductase that binds HMGCoA, is the major rate limiting step in the cholesterol biosynthetic pathway. Several inhibitors of this enzyme are used as potential drugs. The assay of the enzyme is based on labeling the enzyme with radiolabeled HMGCoA and counting (cpm) the labeled enzyme substrate complex in the presence (test) and in the absence (control) of the inhibitor. A bland is set up that contains no enzyme.
- An inhibitor is considered active if it causes more than 65% inhibition. The. cpm Values respectively of control, test and blank samples for inhibitors W, X, Y and Z are given below. State which of the inhibitors is active.
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For each a, b, c, and d options respectively.
The value of % inhibition is For,a = 8000 - 4000 = 50.6 % 8000 - 100 b = 7000 - 1400 = 81.5 % 7000 - 135 c = 7500 - 5000 = 33.7 % 7500 - 90 d = 7200 - 2800 = 62.86 % 7200 - 200 Correct Option: B
For each a, b, c, and d options respectively.
The value of % inhibition is For,a = 8000 - 4000 = 50.6 % 8000 - 100 b = 7000 - 1400 = 81.5 % 7000 - 135 c = 7500 - 5000 = 33.7 % 7500 - 90 d = 7200 - 2800 = 62.86 % 7200 - 200
- The percent inhibition for this enzyme is calculated from the equation
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The amount of radioactivity will be in order
control >test > blank% inhibition = control - test control - blank decrease in enzyme complex = formation due to inhibitor = complex formation in absence of inhibitor maxmimum enzyme- substrate Correct Option: A
The amount of radioactivity will be in order
control >test > blank% inhibition = control - test control - blank decrease in enzyme complex = formation due to inhibitor = complex formation in absence of inhibitor maxmimum enzyme- substrate
Direction: An aliquot of competent E. coli cells were used for determination of cell density by plate count method and another aliquot was used for transformation by plasmid DNA
- Isolated plasmid DNA (5µg) was used for transformation of 100 µl competent E. coli cells to which 900 µl of SOC medium was added. An aliquot of 50ul was plated on a selective plate. After overnight incubation, 300 colonies were observed. Calculate the efficiency of transformation and the percentage of transformed cells per ml of parent culture
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NA
Correct Option: B
NA
- The following culture systems are used for growing large amount of anchorage dependent animal cells except
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Airlift fermenter is a fermenter in which circulation of the culture medium and aeration is achieved by injection of air into some lower part of the fermenter. Usually not suitable for animal cell production.
Correct Option: B
Airlift fermenter is a fermenter in which circulation of the culture medium and aeration is achieved by injection of air into some lower part of the fermenter. Usually not suitable for animal cell production.
