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In the circuit shown in the given, the switch S is open for a long time and closed at t = 0.
The value I at t = 0+ is
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- – 6A
- – 3/2 A
- 3 A
- 9/2 A
Correct Option: A
Voltage across capacitor prior to closing of switch
= 6 × | = 12 V | |
2 |
Immediately after closing of the switch S, the source current is all diverted into the ‘short’
and capacitor furnishes a current of | = 6 A in the 2-ohm resistor. | |
2 |
The direction is opposite to the marked one.
∴ I = – 6A.