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The circuit shown in the given figure is steady-state with switch ‘S’ open. The switch is closed at t = 0. The values of vc (0+) and vc (∞) will be respectively
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- 2 V, 0 V
- 0 V, 2 V
- 2 V, 2 V
- 0 V, 0 V
Correct Option: A
When switchs had been open, the current of 2 A flows through R2 alone. Thus voltage 2 V, and since there is no current in branch 1, the voltage acoss the capacitor is also 2V.
∴ vc (0) = 2
Since after the switching action, voltage across the capacitor cannot change instantaneously,
∴ vc (∞) = vc (0) = 2V.
After the switch is closed and steady state condition reached, the entire current of 2A passes through the closed switch and voltage across the capacitor becomes zero.
