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After closing the switch‘S’ at t = 0, the current i (t) at any instant ‘t’ in the network shown in the given figure will be
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- 10 + 10 e100 t
- 10 – 10 e100 t
- 10 + 10 e–100 t
- 10 – 10 e–100 t
Correct Option: D
It can be certified by checking the value of the current at t = 0+ , and at t = ∞ which should be zero and 10/1 = 10 A respectively.
It is an R-L circuit
∴ i(t) = | [1 - e(– R / L)t] | |
R |