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In the network shown in the given figure, if the voltage V at the time considered is 20 V, then
dV at that time will be dt
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- 1 V/s
- 2 V/s
- – 2 V/s
- zero
Correct Option: B
Given: V = 20 V
∴ Current through 20 ohm resistance = | = 1 A | |
20 |
Voltage across 10 ohm resistor = 40 – 20 = 20 V
Then current through the capacitor = 2 – 1 = 1 A.
∴ C | = | A | ||||
dt | 2 | dt |
⇒ | = 2 V / s. | |
dt |