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When a voltage V0 sin ω0 t is applied to the pure inductor, the ammeter shown in the figure reads I0 . If the voltage applied is
– V0 sin ω0 t + 2 V0 sin 2ω0 t + 3 V0 sin 3ω0 t + 4 V0 sin 4ω0 t
the ammeter reading would be
-
- 0
- 10 I0
- √4² + 3² + 2² + 1 I0
- 2 I0
- 0
Correct Option: D
The importance of inductor for nth harmonic is n times the impedance for the fundamental. Each harmonic gives the same current I0. Therefore, A reads
√I0² + I0² + I0² + I0² = 2I0
