Number Series
Direction: In each of the following questions a number series is given. A number is given after the series and then (a), (b), (c), (d) and (e) are given. According to the given series, you have to form a new series which begins with the given number, and then answer the question asked.

5 5.25 11.5 36.75 3 (a) (b) (c) (d) (e) Which of the following numbers will come in place of (c) ?

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As per the details in the question the series is in the form of
First series :
First term = 5
Second term = First term × 1 + 0.25 × 1 = 5.25
Third term = Second term × 2 + 0.25 × 4 = 11.5
similarly , we can calculate the all next terms .
Second series :
First term = 3
Second term = First term × 1 + 0.25 × 1 = 3.25
Third term = Second term × 2 + 0.25 × 4 = 7.5Correct Option: B
As per the details in the question the series is in the form of
First series :
First term = 5
Second term = First term × 1 + 0.25 × 1
⇒ Second term = 5 × 1 + 0.25 × 1 = 5.25
Third term = Second term × 2 + 0.25 × 4
⇒ Third term = 5.25 × 2 + 0.25 × 4 = 11.5
similarly , we can find the all others terms .
Second series :
First term = 3
Second term = First term × 1 + 0.25 × 1
⇒ Second term = 3 × 1 + 0.25 × 1 = 3.25
Third term = Second term × 2 + 0.25 × 4 = 7.5
⇒ Third term = 3.25 × 2 + 0.25 × 4 = 7.5
Fourth term = Third term × 3 + 0.25 × 9
⇒ Fourth term = 7.5 × 3 + 0.25 × 9 = 24.75
So 24.75 should come in place of (c).
Direction: Which sequence of letters when placed at the blanks one after another will complete the given letter series?
 adb_ac_da_cddcb_dbc_cbda

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From above given series , we can see that
The sequence order of above series is given as
adbcacbdabcddcbadbcacbdaCorrect Option: B
From above given series , we can see that
The sequence order of above series is given as
adbcacbdabcddcbadbcacbda
Hence , required answer will be cbbaa .
 – aba – cabc – dcba – bab – a

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The given series is in the below pattern , we can see that
The series formed is:
a a b a b c a b c d d c b a c b a b a a in which the letters equi–distant from the beginning and end are the same.Correct Option: A
The given series is in the below pattern , we can see that
The series formed is:
a a b a b c a b c d d c b a c b a b a a in which the letters equi–distant from the beginning and end are the same.
Hence , required answer will be abdca .
 b — b — bb — bbb — bb — b

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The series is babb / bbab / bbba / bbbb.
Thus, in each sequence, ‘a’ moves one step forward and ‘b’ takes its place and finally in the fourth sequence, it is eliminated.Correct Option: C
The series is babb / bbab / bbba / bbbb.
Thus, in each sequence, ‘a’ moves one step forward and ‘b’ takes its place and finally in the fourth sequence, it is eliminated.
 c _ bba _ cab _ ac _ ab _ ac

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The given series is in the below pattern , we can see that
cabbac / cabbac / cabbac.Correct Option: B
The given series is in the below pattern , we can see that
cabbac / cabbac / cabbac.
Hence , required answer will be acbcb .