56. Match the following:
    

    NC Code	Definition
    P. M05	1. Absolute coordinate system
    Q. Q01	2. Dwell
    R. Q04	3. Spindle stop
    S. G90	4. Linear interpolation

    
    

1. 1. P–2, Q–3, R–4, S–1

   
   
   

   2. P–3, Q–4, R–1, S–2

   
   
   

   3. P–3, Q–4, R–2, S–1

   
   
   

   4. P–4, Q–3, R–2, S–1

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   NA

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57. In a CNC program block, N002 G02 G91 X40 Z40..., G02 and G91 refer to

1. 1. circular interpolation in counterclockwise direction and incremental dimension

   
   
   

   2. circular interpolation in counterclockwise direction and absolute dimension

   
   
   

   3. circular interpolation in clockwise direction and incremental dimension

   
   
   

   4. circular interpolation in clockwise direction and absolute dimension

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   NA

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58. A CNC vertical milling machine has to cut a straight slot of 10 mm width and 2 mm depth by a cutter of 10 mm diameter between points (0, 0) and (100, 100) on-the XY plane (dimensions in mm). The feed rate used for milling is 50 mm/min. Milling time for the slot (in seconds) is

1. 1. 120

   
   
   

   2. 170

   
   
   

   3. 180

   
   
   

   4. 240

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: B

   NA

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59. For machining a rectangular island represented by coordinates P(0,0), Q(100,0), fl( 100,50) and S(0,50) on a casting using CNC milling machine, an end mill with a diameter of 16 mm is used. The trajectory of the cutter centre to machine the island PQRS is

1. 1. (- 8, - 8), (108, - 8), (108,58), (- 8,58), (- 8, -8)

   
   
   

   2. (8,8), (94,8), (94,44), (8,44), (8,8)

   
   
   

   3. (- 8,8), (94,0), (94,44), (8,44), (- 8,8)

   
   
   

   4. (0,0), (100,0), (100,50), (50,0), (0,0)

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   NA

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60. In an interchangeable assembly, shafts of size 25.000^+0.040-0.010 mm mate with holes of size 25.000^+0.030-0.020 mm. The maximum interference (in microns) in the assembly is

1. 1. 40

   
   
   

   2. 30

   
   
   

   3. 20

   
   
   

   4. 10

   
   
   

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1. View Hint View Answer Discuss in Forum

   Maximum Interference = Allowances = Difference
   Between Maximum Material limit.
   ⇒ D_max for shaft = 25.040mm.
   D_min for Hole = 25.020mm.
   Max. Interference = 25.040 – 25.020 = 20µm

   Correct Option: C

   Maximum Interference = Allowances = Difference
   Between Maximum Material limit.
   ⇒ D_max for shaft = 25.040mm.
   D_min for Hole = 25.020mm.
   Max. Interference = 25.040 – 25.020 = 20µm

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