Highway planning miscellaneous


Highway planning miscellaneous

  1. While designing a hill road with a ruling gradient of 6%, if a sharp horizontal curve of 50 m radius is encountered, the compensated gradient at the curve as per the Indian Roads Congress specifications should be









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    Compensation for ruling gradient =
    30 + R
    = 1.6%
    R

    Max. value =
    75
    = 1.5 %
    R

    ∴ Take 1.5% But as per question, take 1.6%
    ∴ Compensated gradient = 6 – 1.6 = 4.4%

    Correct Option: A

    Compensation for ruling gradient =
    30 + R
    = 1.6%
    R

    Max. value =
    75
    = 1.5 %
    R

    ∴ Take 1.5% But as per question, take 1.6%
    ∴ Compensated gradient = 6 – 1.6 = 4.4%


  1. A vehicle moving at 60 kmph on an ascending gradient of a highway has to come to stop position to avoid collision with a stationary object.The ratio of lag to brake distance is 6: 5. Considering total reaction time of the driver as 2.5 seconds and the coefficient of longitudinal friction as 0.36, the value of ascending gradient (%) is









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    Lag distance = 60 ×
    5
    × 2.5 = 41.67 m
    18

    Lag distance
    =
    6
    Brake distance5

    ∴ Brake distance(s) = 41.67 ×
    5
    = 34.725 m
    6

    S =
    2gƒ + g sin θ

    ∴ 2ƒ + sinθ =
    Sg

    ∴ sinθ =
    - 2ƒ
    Sg

    =
    16.672
    - 2 × 0.36 = 34.75
    34.75 × 9.81

    ∴ θ = 4.8%

    Correct Option: B

    Lag distance = 60 ×
    5
    × 2.5 = 41.67 m
    18

    Lag distance
    =
    6
    Brake distance5

    ∴ Brake distance(s) = 41.67 ×
    5
    = 34.725 m
    6

    S =
    2gƒ + g sin θ

    ∴ 2ƒ + sinθ =
    Sg

    ∴ sinθ =
    - 2ƒ
    Sg

    =
    16.672
    - 2 × 0.36 = 34.75
    34.75 × 9.81

    ∴ θ = 4.8%



  1. Using IRC: 37-1984 “Guidelines for the Design of Flexible Pavements” and the following data, choose the total thickness of the pavement.
    No. of commercial vehicles when construction is completed = 2723 veh/day
    Annual growth rate of the traffic = 5.0%
    Design life of the pavement = 10 years
    Vehicle damage factor = 2.4
    CBR value of the subgrade soil = 5%
    Data for 5% CBR value









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    Axle load =
    365 × A × [(1 + r)n - 1]
    × F
    Y

    =
    365 × 2723 × [(1 + 0.05)10 - 1]
    × F
    0.05

    = 30 × 106axle load = 30 msa
    For 30 msa, thickness = 670 mm

    Correct Option: C

    Axle load =
    365 × A × [(1 + r)n - 1]
    × F
    Y

    =
    365 × 2723 × [(1 + 0.05)10 - 1]
    × F
    0.05

    = 30 × 106axle load = 30 msa
    For 30 msa, thickness = 670 mm


  1. The extra widening required for a two-lane national highway at a horizontal curve of 300 m radius, considering a wheel base of 8 m and a design speed of 100 kmph is









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    Extra widening =
    nL²
    +
    V
    2R9.5√R

    =
    2 × 8²
    +
    100
    2 × 3009.5√300

    = 0.82 m

    Correct Option: C

    Extra widening =
    nL²
    +
    V
    2R9.5√R

    =
    2 × 8²
    +
    100
    2 × 3009.5√300

    = 0.82 m



  1. The specific gravity of paving bitumen as per IS:73-1992 lies between









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    NA

    Correct Option: C

    NA