Highway planning miscellaneous
- While designing a hill road with a ruling gradient of 6%, if a sharp horizontal curve of 50 m radius is encountered, the compensated gradient at the curve as per the Indian Roads Congress specifications should be
-
View Hint View Answer Discuss in Forum
Compensation for ruling gradient = 30 + R = 1.6% R Max. value = 75 = 1.5 % R
∴ Take 1.5% But as per question, take 1.6%
∴ Compensated gradient = 6 – 1.6 = 4.4%Correct Option: A
Compensation for ruling gradient = 30 + R = 1.6% R Max. value = 75 = 1.5 % R
∴ Take 1.5% But as per question, take 1.6%
∴ Compensated gradient = 6 – 1.6 = 4.4%
- A vehicle moving at 60 kmph on an ascending gradient of a highway has to come to stop position to avoid collision with a stationary object.The ratio of lag to brake distance is 6: 5. Considering total reaction time of the driver as 2.5 seconds and the coefficient of longitudinal friction as 0.36, the value of ascending gradient (%) is
-
View Hint View Answer Discuss in Forum
Lag distance = 60 × 5 × 2.5 = 41.67 m 18 Lag distance = 6 Brake distance 5 ∴ Brake distance(s) = 41.67 × 5 = 34.725 m 6 S = v² 2gƒ + g sin θ ∴ 2ƒ + sinθ = v² Sg ∴ sinθ = v² - 2ƒ Sg = 16.672 - 2 × 0.36 = 34.75 34.75 × 9.81
∴ θ = 4.8%Correct Option: B
Lag distance = 60 × 5 × 2.5 = 41.67 m 18 Lag distance = 6 Brake distance 5 ∴ Brake distance(s) = 41.67 × 5 = 34.725 m 6 S = v² 2gƒ + g sin θ ∴ 2ƒ + sinθ = v² Sg ∴ sinθ = v² - 2ƒ Sg = 16.672 - 2 × 0.36 = 34.75 34.75 × 9.81
∴ θ = 4.8%
- Using IRC: 37-1984 “Guidelines for the Design of Flexible Pavements” and the following data, choose the total thickness of the pavement.
No. of commercial vehicles when construction is completed = 2723 veh/day
Annual growth rate of the traffic = 5.0%
Design life of the pavement = 10 years
Vehicle damage factor = 2.4
CBR value of the subgrade soil = 5%
Data for 5% CBR value
-
View Hint View Answer Discuss in Forum
Axle load = 365 × A × [(1 + r)n - 1] × F Y = 365 × 2723 × [(1 + 0.05)10 - 1] × F 0.05
= 30 × 106axle load = 30 msa
For 30 msa, thickness = 670 mmCorrect Option: C
Axle load = 365 × A × [(1 + r)n - 1] × F Y = 365 × 2723 × [(1 + 0.05)10 - 1] × F 0.05
= 30 × 106axle load = 30 msa
For 30 msa, thickness = 670 mm
- The extra widening required for a two-lane national highway at a horizontal curve of 300 m radius, considering a wheel base of 8 m and a design speed of 100 kmph is
-
View Hint View Answer Discuss in Forum
Extra widening = nL² + V 2R 9.5√R = 2 × 8² + 100 2 × 300 9.5√300
= 0.82 mCorrect Option: C
Extra widening = nL² + V 2R 9.5√R = 2 × 8² + 100 2 × 300 9.5√300
= 0.82 m
- The specific gravity of paving bitumen as per IS:73-1992 lies between
-
View Hint View Answer Discuss in Forum
NA
Correct Option: C
NA