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While designing a hill road with a ruling gradient of 6%, if a sharp horizontal curve of 50 m radius is encountered, the compensated gradient at the curve as per the Indian Roads Congress specifications should be
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- 4.4%
- 4.75%
- 5.0%
- 5.25%
Correct Option: A
| Compensation for ruling gradient = | = 1.6% | |
| R |
| Max. value = | = 1.5 % | |
| R |
∴ Take 1.5% But as per question, take 1.6%
∴ Compensated gradient = 6 – 1.6 = 4.4%
