Highway planning miscellaneous


Highway planning miscellaneous

  1. The penetration value of bitumen sample tested at 25°C is 80. When this sample is heated to 60°C and tested again, the needle of the penetration test apparatus penetrates the bitumen sample by d mm. The value of d CANNOT be less than _____ mm.









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    8

    Correct Option: D

    8


  1. The probability that k number of vehicles arrive (i.e. cross a predefined line) in time t is given as (λt)ke-λt/k! where λ is the average vehicle arrival rate. What is the probability that the time headway is greater than or equal to time t1 ?









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    Probability of k vehicles arrival,

    P(k) =
    (λt)ke-λt1
    k!

    Time headway ≥ t1 means no vehicle arrives i.e., k = 0
    ∴ P(k) = e-λt1

    Correct Option: D

    Probability of k vehicles arrival,

    P(k) =
    (λt)ke-λt1
    k!

    Time headway ≥ t1 means no vehicle arrives i.e., k = 0
    ∴ P(k) = e-λt1



  1. A vehicle negotiates a transition curve with uniform speed v. If the radiuses of the horizontal curve and the allowable jerk are R and J, respectively, the minimum length of the transition curve is









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    L =
    JR

    Jerk, J is the rate of change of acceleration.

    Correct Option: D

    L =
    JR

    Jerk, J is the rate of change of acceleration.


  1. If v is the initial speed of a vehicle, g is the gravitational acceleration, G is the upward longitudinal slope of the road and ƒ>sub>r is the coefficient of rolling friction during braking, the braking distance (measured horizontally) for the vehicle to stop is









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    L =
    2g (ƒ + G)

    Correct Option: B

    L =
    2g (ƒ + G)



  1. A pavement designer has arrived at a design traffic of 100 million standard axles for a newly developing national highway as per IRC:37 guidelines using the following data:
    Design life = 15 years
    Commercial vehicle count before pavement construction = 4500 vehicles/day
    Annual traffic growth rate = 8%.
    The vehicle damage factor used in the calculation was









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    msa =
    365A[(1 + r)h]
    × F
    r

    100 × 106 = 365 × 45001 +
    8
    15 - 1
    100
    8
    100

    ∴ F = 2.24

    Correct Option: B

    msa =
    365A[(1 + r)h]
    × F
    r

    100 × 106 = 365 × 45001 +
    8
    15 - 1
    100
    8
    100

    ∴ F = 2.24