Fluid Mechanics and Hydraulic Machinery Miscellaneous


Fluid Mechanics and Hydraulic Machinery Miscellaneous

Fluid Mechanics and Hydraulic Machinery

  1. In the case of turbulent flow of a fluid though a circular tube (as compared to the case of laminar flow at the same flow rate) the maximum velocity is _________shear stress at the wall is _______, and the pressure drop across a given length is __________ The correct words for the blanks are, respectively









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    NA

    Correct Option: C

    NA


  1. Prandtl's mixing length in turbulent flow signifies









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    NA

    Correct Option: A

    NA



  1. Match the following
    P: Compressible flowU: Reynolds number
    Q: Free surface flowV: Nusselt number
    R: Boundary layer flowW:Weber number
    S: Pipe flowX: Froude number
    T: Heat convectionY: Mach number
    Z: Skin friction coefficient









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    NA

    Correct Option: D

    NA


  1. Consider the turbulent flow of a fluid through a circular pipe of diameter D.Identify the correct pair of statements. I. The fluid is well-mixed
    II. The fluid is unmixed
    III.ReD < 2300
    IV. ReD > 2300









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    ReD > 2300 means it is a turbulent flow. I n turbulent flow, the fluid is well mixed. The fluid is unmixed, for a very-low Reynolds number laminar flow.

    Correct Option: D

    ReD > 2300 means it is a turbulent flow. I n turbulent flow, the fluid is well mixed. The fluid is unmixed, for a very-low Reynolds number laminar flow.



  1. For a fluid flow through a divergent pipe of length L having inlet and outlet radii of R1, and R2 respectively and a constant flow rate of Q, assuming the velocity to be axial and uniform at any cross-section, the acceleration at the exit is









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    Velocity at inlet,

    u1 =
    Q
    πR²1

    Velocity at outlet,
    u2 =
    Q
    πR²2


    Acceleration =
    v.du
    dx

    du
    =
    u2 - u1
    =
    Q
    1
    -
    2
    dxLπL21

    Acceleration at the exit = u2.
    dv
    dx

    =
    Q
    Q
    1 - R²2
    πR²2πL12

    =
    (R1 - R2)(R1 + R2)
    π²R²1L12

    Consider limiting case, i.e. R1 → R2, we have
    Acceleration at the exit =
    π²R²LL

    h = x
    (R1 - R2)(R1 + R2)
    =
    2Q²(R1 - R2)
    R42π²R52L

    Correct Option: C

    Velocity at inlet,

    u1 =
    Q
    πR²1

    Velocity at outlet,
    u2 =
    Q
    πR²2


    Acceleration =
    v.du
    dx

    du
    =
    u2 - u1
    =
    Q
    1
    -
    2
    dxLπL21

    Acceleration at the exit = u2.
    dv
    dx

    =
    Q
    Q
    1 - R²2
    πR²2πL12

    =
    (R1 - R2)(R1 + R2)
    π²R²1L12

    Consider limiting case, i.e. R1 → R2, we have
    Acceleration at the exit =
    π²R²LL

    h = x
    (R1 - R2)(R1 + R2)
    =
    2Q²(R1 - R2)
    R42π²R52L