Fluid Mechanics and Hydraulic Machinery Miscellaneous
- In the case of turbulent flow of a fluid though a circular tube (as compared to the case of laminar flow at the same flow rate) the maximum velocity is _________shear stress at the wall is _______, and the pressure drop across a given length is __________ The correct words for the blanks are, respectively
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NA
Correct Option: C
NA
- Prandtl's mixing length in turbulent flow signifies
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NA
Correct Option: A
NA
- Match the following
P: Compressible flow U: Reynolds number Q: Free surface flow V: Nusselt number R: Boundary layer flow W:Weber number S: Pipe flow X: Froude number T: Heat convection Y: Mach number Z: Skin friction coefficient
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NA
Correct Option: D
NA
- Consider the turbulent flow of a fluid through a circular pipe of diameter D.Identify the correct pair of statements. I. The fluid is well-mixed
II. The fluid is unmixed
III.ReD < 2300
IV. ReD > 2300
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ReD > 2300 means it is a turbulent flow. I n turbulent flow, the fluid is well mixed. The fluid is unmixed, for a very-low Reynolds number laminar flow.
Correct Option: D
ReD > 2300 means it is a turbulent flow. I n turbulent flow, the fluid is well mixed. The fluid is unmixed, for a very-low Reynolds number laminar flow.
- For a fluid flow through a divergent pipe of length L having inlet and outlet radii of R1, and R2 respectively and a constant flow rate of Q, assuming the velocity to be axial and uniform at any cross-section, the acceleration at the exit is
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Velocity at inlet,
u1 = Q πR²1
Velocity at outlet,u2 = Q πR²2 Acceleration = v.du dx ∴ du = u2 - u1 = Q R²1 - R²2 dx L πL R²2 R²1 Acceleration at the exit = u2. dv dx = Q Q R²1 - R²2 πR²2 πL R²1 R²2 = Q² (R1 - R2)(R1 + R2) π²R²1L R²1 R²2
Consider limiting case, i.e. R1 → R2, we haveAcceleration at the exit = Q² π²R²LL h = x (R1 - R2)(R1 + R2) = 2Q²(R1 - R2) R42 π²R52L Correct Option: C
Velocity at inlet,
u1 = Q πR²1
Velocity at outlet,u2 = Q πR²2 Acceleration = v.du dx ∴ du = u2 - u1 = Q R²1 - R²2 dx L πL R²2 R²1 Acceleration at the exit = u2. dv dx = Q Q R²1 - R²2 πR²2 πL R²1 R²2 = Q² (R1 - R2)(R1 + R2) π²R²1L R²1 R²2
Consider limiting case, i.e. R1 → R2, we haveAcceleration at the exit = Q² π²R²LL h = x (R1 - R2)(R1 + R2) = 2Q²(R1 - R2) R42 π²R52L