Electronic measurements and instrumentation miscellaneous

Electronic measurements and instrumentation miscellaneous

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Electronic Measurements And Instrumentation

Electronic measurements and instrumentation miscellaneous
  1. A 10 V full-scale voltmeter having 100 k-ohm/V sensitivity is used to measure the output of a photovoltaic cell having an internal resistance of 1 M-ohm. The voltmeter reads 5V. The voltage generated by the photovoltaic cell is:








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    Let the voltage generated by the photovoltaic cell is E.
    Given, Sensitivity of voltmeter = 100 k-ohm/V
    Internal resistance of photovoltaic cell,
    Rr = 1MΩ
    Voltmeter range = 0–10V
    Voltmeter range = 5V
    The resistance of voltmeter
    = Sensitivity × Maximum voltmeter range
    = 100 k-ohm/V × 10 = 1MΩ
    Ifsd = 1/sensitivity = 1/100 k-ohm/V = 10μA
    Now, combining these information with the help of circuit diagram given below:
    From above figure we conclude that
    E = 10V


    Correct Option: B

    Let the voltage generated by the photovoltaic cell is E.
    Given, Sensitivity of voltmeter = 100 k-ohm/V
    Internal resistance of photovoltaic cell,
    Rr = 1MΩ
    Voltmeter range = 0–10V
    Voltmeter range = 5V
    The resistance of voltmeter
    = Sensitivity × Maximum voltmeter range
    = 100 k-ohm/V × 10 = 1MΩ
    Ifsd = 1/sensitivity = 1/100 k-ohm/V = 10μA
    Now, combining these information with the help of circuit diagram given below:
    From above figure we conclude that
    E = 10V


  1. LVDT:








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    LVDT converts linear motion into electrical signal.

    Correct Option: A

    LVDT converts linear motion into electrical signal.

  1. If an instrument has a cramped scale for larger values of indicated quantity, it should obey a:








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    NA

    Correct Option: B

    NA

  1. If an energy meter disc makes 10 revolutions in 100 seconds when a load of 450 W is connected to it, the meter constant (in rev/k Wh) is:








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    Given, No. of revolutions = 10
    t = 100 sec
    p = 450W

    K =
    10
    		Rev/W-sec
    450 × 100

    or
    K =
    10 × 3600 × 1000
    		Rev/W-sec
    450 × 100

    or
    K = 800

    Correct Option: D

    Given, No. of revolutions = 10
    t = 100 sec
    p = 450W

    K =
    10
    		Rev/W-sec
    450 × 100

    or
    K =
    10 × 3600 × 1000
    		Rev/W-sec
    450 × 100

    or
    K = 800

  1. Two resistance 100Ω ± 5Ω and 150Ω ± 15Ω are connected in series. If the errors are specified as standard deviations, the resultant error will be:








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    Given, R1 = 100Ω ± 5Ω
    R2 = 150Ω ± 15Ω
    RT = R1 + R2 (as they are connected in series)
    There errors are specified at standard deviations are probable errors. In this case the resultant error.
    R = ñ R12 + R22
    = ñ 52 + 132
    = ± 15·8Ω

    Correct Option: C

    Given, R1 = 100Ω ± 5Ω
    R2 = 150Ω ± 15Ω
    RT = R1 + R2 (as they are connected in series)
    There errors are specified at standard deviations are probable errors. In this case the resultant error.
    R = ñ R12 + R22
    = ñ 52 + 132
    = ± 15·8Ω