Electromagnetic theory miscellaneous
- The equation for distortionless transmission if R/ G = L/ C. To attain it, in a line—
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It is best to increase L for distortionless transmission.
Correct Option: A
It is best to increase L for distortionless transmission.
- Match List-I with List-II and select the correct answer using the codes given the lists:
List-I List-II (Maxwell's equation) (a) ∇ × H = J + ∂D/∂t 1. Faraday's law (b) ∇ × E = −∂B/∂t 2. Gauss' law (c) ∇ ⋅ D = ρ 3.Ampere's law
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NA
Correct Option: D
NA
- When a lossy capacitor with a dielectric of permittivity ε and conductivity σ operates at a frequency ω, the loss tangent for the capacitor is given by—
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tan δ = IR = V Ic RVωC
= 1/ωCR
C = A∈/d,
R = d/σA∴ CR = A∈ d = ∈ d σA σ ∴ tan δ = 1 = ∈ ω∈/σ ω∈
Correct Option: C
tan δ = IR = V Ic RVωC
= 1/ωCR
C = A∈/d,
R = d/σA∴ CR = A∈ d = ∈ d σA σ ∴ tan δ = 1 = ∈ ω∈/σ ω∈
- Two electric dipoles aligned parallel to each other and having the same axis exert a force F on each other, when a distance d apart. If the dipoles are a distance 2d apart, then the mutual force between them would be—
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The force of repulsion between the two dipoles
F = q2 1 – 1 2πεd2 [1 + (I2/d2)]
Assuming that I << d, we haveF = q2 1 – 1 + 3 3 2πεd2 2 d2 F = q2 2πεd2
Therefore, if with distance d, the force is F, the force with distance 2d would be F/16.Correct Option: D
The force of repulsion between the two dipoles
F = q2 1 – 1 2πεd2 [1 + (I2/d2)]
Assuming that I << d, we haveF = q2 1 – 1 + 3 3 2πεd2 2 d2 F = q2 2πεd2
Therefore, if with distance d, the force is F, the force with distance 2d would be F/16.
- If a conductor of cross-section A and carrying a current current | →a y| is oriented along the y-axis in a magnetic field B = B0 →a x + B0 →a y, the force density exerted on the conductor is—
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The force on a current carrying mass lying in a magnetic field B is given by
F = . (J × B) dv vol
J = 1/y iy
∴ The force density = 1/y iy × B0 (ix + iy)
= 1/a B0 (– iz) N/m3
= B0/a →a>z N/m3
Hence alternative (C) is the correct choice.
Correct Option: C
The force on a current carrying mass lying in a magnetic field B is given by
F = . (J × B) dv vol
J = 1/y iy
∴ The force density = 1/y iy × B0 (ix + iy)
= 1/a B0 (– iz) N/m3
= B0/a →a>z N/m3
Hence alternative (C) is the correct choice.