Electromagnetic theory miscellaneous


Electromagnetic theory miscellaneous

Electromagnetic Theory

  1. The equation for distortionless transmission if R/ G = L/ C. To attain it, in a line—









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    It is best to increase L for distortionless transmission.

    Correct Option: A

    It is best to increase L for distortionless transmission.


  1. Match List-I with List-II and select the correct answer using the codes given the lists:
    List-IList-II
    (Maxwell's equation)
    (a) ∇ × H = J + ∂D/∂t1. Faraday's law
    (b) ∇ × E = −∂B/∂t 2. Gauss' law
    (c) ∇ ⋅ D = ρ3.Ampere's law









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    NA

    Correct Option: D

    NA



  1. When a lossy capacitor with a dielectric of permittivity ε and conductivity σ operates at a frequency ω, the loss tangent for the capacitor is given by—









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    tan δ =
    IR
    =
    V
    IcRVωC

    = 1/ωCR
    C = A∈/d,
    R = d/σA
    ∴ CR =
    A
    d
    =
    dσAσ

    ∴ tan δ =
    1
    =
    ω∈/σω∈


    Correct Option: C

    tan δ =
    IR
    =
    V
    IcRVωC

    = 1/ωCR
    C = A∈/d,
    R = d/σA
    ∴ CR =
    A
    d
    =
    dσAσ

    ∴ tan δ =
    1
    =
    ω∈/σω∈



  1. Two electric dipoles aligned parallel to each other and having the same axis exert a force F on each other, when a distance d apart. If the dipoles are a distance 2d apart, then the mutual force between them would be—









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    The force of repulsion between the two dipoles

    F =
    q2
    1 –
    1
    2πεd2[1 + (I2/d2)]

    Assuming that I << d, we have
    F =
    q2
    1 – 1 +
    3
    3
    2πεd22d2

    F =
    q2
    2πεd2

    Therefore, if with distance d, the force is F, the force with distance 2d would be F/16.

    Correct Option: D

    The force of repulsion between the two dipoles

    F =
    q2
    1 –
    1
    2πεd2[1 + (I2/d2)]

    Assuming that I << d, we have
    F =
    q2
    1 – 1 +
    3
    3
    2πεd22d2

    F =
    q2
    2πεd2

    Therefore, if with distance d, the force is F, the force with distance 2d would be F/16.



  1. If a conductor of cross-section A and carrying a current current | a y| is oriented along the y-axis in a magnetic field B = B0 a x + B0 a y, the force density exerted on the conductor is—









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    The force on a current carrying mass lying in a magnetic field B is given by

    F = .(J × B) dv
    vol

    J = 1/y iy
    ∴ The force density = 1/y iy × B0 (ix + iy)
    = 1/a B0 (– iz) N/m3
    = B0/a a>z N/m3
    Hence alternative (C) is the correct choice.

    Correct Option: C

    The force on a current carrying mass lying in a magnetic field B is given by

    F = .(J × B) dv
    vol

    J = 1/y iy
    ∴ The force density = 1/y iy × B0 (ix + iy)
    = 1/a B0 (– iz) N/m3
    = B0/a a>z N/m3
    Hence alternative (C) is the correct choice.