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If a conductor of cross-section A and carrying a current current | →a y| is oriented along the y-axis in a magnetic field B = B0 →a x + B0 →a y, the force density exerted on the conductor is—
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→ + B0 az N/m2 a -
→ + B0 ax N/m2 a -
→ − B0 az N/m3 a -
→ + B0 ay N/m3 a
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Correct Option: C
The force on a current carrying mass lying in a magnetic field B is given by
F = | ![]() | . | (J × B) dv | vol |
J = 1/y iy
∴ The force density = 1/y iy × B0 (ix + iy)
= 1/a B0 (– iz) N/m3
= B0/a →a>z N/m3
Hence alternative (C) is the correct choice.