Electromagnetic theory miscellaneous


Electromagnetic theory miscellaneous

Electromagnetic Theory

  1. 160. Match the following:
    (A) ∇ × H = J
    (B) ƒOs E·dl = –d/dt ƒs B·ds
    (C) ∇ · J = –δρ/∇t
    1. Continuity equation
    2. Faraday's law
    3. Ampere's law
    4. Gauss's law
    5. Biot-Savart law









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    NA

    Correct Option: D

    NA


  1. For a dipole antenna—









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    In a dipole antenna radiation is almost nil along its axis and maximum in a direction perpendicular to its axis.

    Correct Option: A

    In a dipole antenna radiation is almost nil along its axis and maximum in a direction perpendicular to its axis.



  1. A plane electromagnetic wave travelling along +z-direction, has its electric field given by Ex = 2 cos (t) and Ey = 2 cos (t + 90) the wave is—









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    Ex = 2 cos ωt,
    Ey = 2 cos (ωt + 90º)
    = – 2 sin ωt
    Ey/ Ex = – tan ωt
    This is a left circularly polarized wave.

    Correct Option: C

    Ex = 2 cos ωt,
    Ey = 2 cos (ωt + 90º)
    = – 2 sin ωt
    Ey/ Ex = – tan ωt
    This is a left circularly polarized wave.


  1. Consider a transmission line of characteristics impedance 50 ohm. Let it be terminated at one end by + j 50 ohm. The VSWR produced by it in the transmission line will be—









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    Reflection coefficient is given by

    ρ =
    ZL − Z0
    =
    j 50 − 50
    ZL + Z0j 50 + 50

    Hence    |ρ| =
    (502 + 502)/ √(502 + 502)
    and the VSWR =
    1 + |ρ|
    =
    2
    = ∞
    1 − |ρ|0

    Correct Option: C

    Reflection coefficient is given by

    ρ =
    ZL − Z0
    =
    j 50 − 50
    ZL + Z0j 50 + 50

    Hence    |ρ| =
    (502 + 502)/ √(502 + 502)
    and the VSWR =
    1 + |ρ|
    =
    2
    = ∞
    1 − |ρ|0



  1. A transmission line whose characteristic impedance is a pure resistance—











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    We know that,

    Z0 =
    R + jωL
    G + jωC

    With Z0 as pure resistance, we have
    Z0 = R + j0
    1. Lossless line has: R = G = 0;
    ∴ Z0 = √L/C
    2. Distortionless line: R/ G = L/C
    3. L = 0, C = 0,   Z = √R/G Thus transmission line may be lossless, distortionless or with L = C = 0.

    Correct Option: E

    We know that,

    Z0 =
    R + jωL
    G + jωC

    With Z0 as pure resistance, we have
    Z0 = R + j0
    1. Lossless line has: R = G = 0;
    ∴ Z0 = √L/C
    2. Distortionless line: R/ G = L/C
    3. L = 0, C = 0,   Z = √R/G Thus transmission line may be lossless, distortionless or with L = C = 0.