Moving Charges and Magnetism


Moving Charges and Magnetism

  1. A straight wire of diameter 0.5 mm carrying a current of 1 A is replaced by another wire of 1 mm diameter carrying same current. The strength of magnetic field far away is​​









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    B =
    μ0i
    2πr

    and so it is independent of thickness. ​
    The current is same in both the wires, hence magnetic field induced will be same.

    Correct Option: B

    B =
    μ0i
    2πr

    and so it is independent of thickness. ​
    The current is same in both the wires, hence magnetic field induced will be same.


  1. At what distance from a long straight wire carrying a current of 12 A will the magnetic field be equal to 3 × 10-5 Wb/m² ?​









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    Current (I) = 12 A and magnetic field (B) = 3 × 10–5 Wb/m². Consider magnetic field B at distance r.

    Magnetic field , B =
    μ0I
    2πr

    ⇒ r =
    μ0I
    =
    (4π × 10-7) × 12
    = 8 × 10-2m
    2πB2 × π × (3 × 10-5)

    Correct Option: A

    Current (I) = 12 A and magnetic field (B) = 3 × 10–5 Wb/m². Consider magnetic field B at distance r.

    Magnetic field , B =
    μ0I
    2πr

    ⇒ r =
    μ0I
    =
    (4π × 10-7) × 12
    = 8 × 10-2m
    2πB2 × π × (3 × 10-5)



  1. The magnetic field at a distance r from a long wire carrying current i is 0.4 tesla. The magnetic field at a distance 2r is​​









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    B =
    μ0i
    or B ∝
    1
    2πrr

    ​When r is doubled, the magnetic field becomes half, i.e., now the magnetic field will be 0.2 T.

    Correct Option: A

    B =
    μ0i
    or B ∝
    1
    2πrr

    ​When r is doubled, the magnetic field becomes half, i.e., now the magnetic field will be 0.2 T.


  1. The magnetic induction at a point P which is at a distance of 4 cm from a long current carrying wire is 10-3 T. The field of induction at a distance 12 cm from the current will be









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    B =
    μ0I
    ⇒ B ∝
    1
    2πrr

    As the distance is increased to three times, the magnetic induction reduces to one third. Hence,
    B =
    1
    × 10-3 tesla = 3.33 × 10-4 tesla
    3

    Correct Option: A

    B =
    μ0I
    ⇒ B ∝
    1
    2πrr

    As the distance is increased to three times, the magnetic induction reduces to one third. Hence,
    B =
    1
    × 10-3 tesla = 3.33 × 10-4 tesla
    3



  1. Energy in a current carrying coil is stored in the form of​









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    Energy is stored in magnetic field.

    Correct Option: B

    Energy is stored in magnetic field.