Alternating Current


Alternating Current

  1. An inductance L having a resistance R is connected to an alternating source of angular frequency ω. The quality factor Q of the inductance is​​









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    Quality Factor =
    Potential drop accross capacitor or inductor
    Potential drop accross R

    = IωL = ωL
    IRR

    Correct Option: D

    Quality Factor =
    Potential drop accross capacitor or inductor
    Potential drop accross R

    = IωL = ωL
    IRR


  1. A capacitor has capacity C and reactance X. If capacitance
    and frequency become double, then reactance will be​​









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    Capacitive reactance,

    X = 1 = 1
    ωC2πƒC

    ⇒ X ∝ 1
    ƒ C

    X'= ƒ × Cƒ× C = 1
    Xƒ'C'2C4

    ⇒ X' =
    X
    4

    Correct Option: C

    Capacitive reactance,

    X = 1 = 1
    ωC2πƒC

    ⇒ X ∝ 1
    ƒ C

    X'= ƒ × Cƒ× C = 1
    Xƒ'C'2C4

    ⇒ X' =
    X
    4



  1. In a series resonant circuit, having L, C and R as its elements, the resonant current is i. The power dissipated in the circuit at resonance is
    where ω is the angular resonance frequency.









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    At resonance Lω = 1

    = 1
    LC

    Current through circuit i = E
    R

    Power dissipated at Resonance = i²R

    Correct Option: D

    At resonance Lω = 1

    = 1
    LC

    Current through circuit i = E
    R

    Power dissipated at Resonance = i²R


  1. A coil of 40 henry inductance is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is









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    Time constant is L/R ​
    Given, L = 40H & R = 8Ω ​
    ∴ τ = 40/8 = 5 sec.

    Correct Option: B

    Time constant is L/R ​
    Given, L = 40H & R = 8Ω ​
    ∴ τ = 40/8 = 5 sec.



  1. In a circuit, L, C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45°. The value of C is​​









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    ​From figure,

    tan 45º = (1/ωC) - ωL
    R

    1- ωL = R
    ωC

    1= R + ωL
    ωC

    ∴ ω = = 2μƒ
    T

    C = 1 = 1
    ω(R + ωL)2πƒ(R + 2πƒ L)

    Correct Option: D

    ​From figure,

    tan 45º = (1/ωC) - ωL
    R

    1- ωL = R
    ωC

    1= R + ωL
    ωC

    ∴ ω = = 2μƒ
    T

    C = 1 = 1
    ω(R + ωL)2πƒ(R + 2πƒ L)