Electrical machines miscellaneous
- A single phase, 50 kVA, 1000V/100 V two winding transformer is connected as an autotransformer as shown in the figure.
The kVA rating of the autotransformer is ______.
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KVA rating of Auto transfer = 1000 V × 550 A = 550 KVA
or, = 1100 V × 500 A = 550 KVA.Correct Option: B
KVA rating of Auto transfer = 1000 V × 550 A = 550 KVA
or, = 1100 V × 500 A = 550 KVA.
- A 15kW, 230 V dc shunt motor has armature ci r cuit r esi st ance of 0.4 Ω and field cir cuit resistance of 230 Ω. At no load and rated voltage, the motor runs at 1400 rpm and the line current drawn by the motor is 5 A. At full load, the motor draws a line current of 70A. Neglect armature reaction. The full load speed of the motor in rpm is ________.
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Given 15kW, 230V dc shunt motor armature resistance Ra = 0.4 Ω
Field resistance, Rsh = 230 Ω
∴ Eb1 = 230 – 4 × 0.4 = 228.4 V
∴ Eb2 = 230 – 69 × 0.4 = 202.4 V∴ N2 = Eb2 × φ1 N1 Eb1 φ2 = Eb2 (∵ Flux is constant) Eb1 N2 = N1 × Eb2 Eb1 = 1400 × 202.4 = 1240 rpm 228.4
Correct Option: C
Given 15kW, 230V dc shunt motor armature resistance Ra = 0.4 Ω
Field resistance, Rsh = 230 Ω
∴ Eb1 = 230 – 4 × 0.4 = 228.4 V
∴ Eb2 = 230 – 69 × 0.4 = 202.4 V∴ N2 = Eb2 × φ1 N1 Eb1 φ2 = Eb2 (∵ Flux is constant) Eb1 N2 = N1 × Eb2 Eb1 = 1400 × 202.4 = 1240 rpm 228.4
- A star connected 400V, 50Hz, 4 pole synchronous machine gave the following open circuit and short circuit test results :
Open circuit test : Voc = 400 V (rms, line-to-line) at field current, If = 2.3 A
Short circuit test : Isc = 10 A (rms, phase) at field current, If = 1.5 A
The value of per phase synchronous impedance in Ω at rated voltage is _____________
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For open circuit test :
VOC = 400 V (L – L)1 If = 2.3 A
For short circuit test :
ISC = 10 A (phase), If = 1.5 A
We know,∴ ISC = 2.3 × 10 = 15.33 A 1.5 ∴ Zs = VOC ISC = 400 / √3 = 15.06 15.33
= 15.06 Ω / ph
Correct Option: B
For open circuit test :
VOC = 400 V (L – L)1 If = 2.3 A
For short circuit test :
ISC = 10 A (phase), If = 1.5 A
We know,∴ ISC = 2.3 × 10 = 15.33 A 1.5 ∴ Zs = VOC ISC = 400 / √3 = 15.06 15.33
= 15.06 Ω / ph
- An 8-pole, 3-phase, 50 Hz induction motor is operating at a speed of 700 rpm. The frequency of the rotor current of the motor in Hz is _______
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Given, P = 9, f = 50 Hz, N = 700 rpm
4 Frequency of Rotor current = s.f.S = Ns - N = 750 - 700 = 0.067 Ns 750
∴ fr = (0.067) × 50 = 3.33 HzCorrect Option: C
Given, P = 9, f = 50 Hz, N = 700 rpm
4 Frequency of Rotor current = s.f.S = Ns - N = 750 - 700 = 0.067 Ns 750
∴ fr = (0.067) × 50 = 3.33 Hz
- With an armature voltage of 100V and rated field winding voltage, the speed of a separately excited DC motor driving a fan is 1000 rpm, and its armature current is 10A. The armature resistance is 1Ω. The load torque of the fan load i s proportional to the square of the rotor speed. Neglecting rotational losses, the value of the armature voltage (in Volt) which will reduce the rotor speed to 500 rpm is ___________.
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NA
Correct Option: A
NA