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A DNA fragment of 4500 bp has to be tailed with dT residues by using dTTP and the enzyme ‘terminal transferase’. The stock solution of dTTP that is used as a substrate has a concentration of 150µM. Ten µl of this stock solution is added to a total volume of 200µl reaction. What will be the concentration of dTTP in the reaction?
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- 7.5 µM
- 75 µM
- 0.75 µM
- 0.075 µM
Correct Option: A
Stock solution= 150 µM
Dilution factor= 10/200 µl = 1/20 µl
Concentration of d TTP= (1/20)*150 µM= 7.5 µM
