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In a chemostat, evaluate the dilution rate at the cell wash-out condition by applying Monod’smodel with the given set of data: µmax = 1h–1;Yx/s = 0.5 g g–1; Ks = 0.2 g L–1; S0 = 10 g L–1
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- 1.00 h–1
- 0.49 h–1
- 0.98 h–1
- 1.02 h–1
Correct Option: C
We know, from Monod's equation
μ = μmax [S0/(KS + S0)]
⇒ μ = 1 * [10/(0.2 +10)] = 10/10.2 = 0.98
At wash out, Dilution rate D = μ
Therefore,
the required dilution rate = 0.98 hr–1
