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Initially, the circuit shown in the given figure was relaxed. If switch is closed at t = 0, then
values of i(0+), di (0+) and d2i (0+) will respectively be dt dt2 
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- 0, 10 and – 100
- 0, 10 and 100
- 10, 100 and 0
- 100, 0 and 10
Correct Option: A
By KVL equation
| 10 = i R + | + Vc ......(i) | |
| dt |
At t = 0+, t = 0 and Vc = 0 (short-circuited)
Differentiating equation (i), we have
| 10 = | R + | + | |||
| dt | dt2 | dt |
| ⇒ | = - | R ...... |  | as | = | = 0 |  | ||||
| dt2 | dt | dt | C |
| ⇒ | = - 10 × 10 = - 100 | |
| dt2 |
