V-I relation for the network shown in the given box is V

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V-I relation for the network shown in the given box is V = 4I – 9. I f now a resistor R = 2 Ω is connected across it, then value of I will be

1. – 4.5 A
2. – 1.5 A
3. 1.5 A
4. 4.5 A

Correct Option: C

V = 4I – 9 = – IR
⇒ 4I – 9 = – 2I
⇒ I = 1.5 A