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Assuming both the voltage sources are in phase, the value of R for which maximum power is transferred from circuit A to circuit B is

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- 0.8 Ω
- 1. 4 Ω
- 2 Ω
- 2.8 Ω
Correct Option: A
Power transferred from circuit A to circuit B
| P = VI = | ![]() | ![]() | . | ![]() | ![]() | = | |||
| R + 2 | R + 2 | (R + 2)2 |
| I = | = | |||
| 2 + R | 2 + R |
| V = 3 + IR = 3 + | = | |||
| 2 + R | 2 + R |
| ∴ | = | = 0 | ||
| dR | (R + 2)4 |

⇒ 70(R + 2)2 = (42 + 70R) 2 (R + 2)
⇒ 5(R + 2) = 2(3 + 5R)
⇒ 5R + 10 = 6 + 10R
4 = 5R
⇒ R = 0.8 Ω

