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H(z) is a transfer function of a real system. When a signal x[n] = (t + j)n is the input to such a system, the output is zero. Further, the Region Of Convergence (ROC) of
1 - 1 z-1 2
H(z) is the entire Z-plane (except z = 0). It can then be inferred that H(z) can have a minimum of
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- one pole and one zero
- one pole and two zero
- two poles and one zero
- two poles and two zeros
Correct Option: B
It will have minimum 1 pole and 2 zeros.
ROC = | ![]() | 1 - | z-1 | ![]() | H(z) = | H(z) | ||
2 | 2z |
∴ H(z) will be in the form of | , | |
(2z - 1) |
Hence for minimum realization, n = 2
H(z) = | , | |
(2z - 1) |