-
Let x(t) = rect t - 1 (where rect (x) = 1 2 for - 1 ≤ x ≤ 1 and zero otherwise). 2 2 Then if since (x) = sin (πx) , πx
then Fourier Transform of x(t) + x(– t) will be given by
-
-
sinc ω 2π -
2sinc ω 2π -
2sinc ω cos ω 2π 2 -
sinc ω sin ω 2π 2
-
Correct Option: C
rect(x) =1 for | ≤ x ≤ | .......(1) | ||
2 | 2 |
Given x(t) = rect | ![]() | t - | ![]() | |
2 |
Simplifying x(t) with the help of equation (1).
∴ x(t) = 1, 0 ≤ t ≤ 1
