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In the network shown in the given figure, if the voltage V at the time considered is 20 V, then dV/ dt at that time will be
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- 1 V/s
- 2 V/s
- – 2 V/s
- zero
- 1 V/s
Correct Option: B
Given: V = 20 V
| Current through 20 ohm resistance = | = 1 amp | |
| 20 |
Voltage across 10 ohm resistor = 40 – 20 = 20 V
Current through the capacitor = 2 – 1 = 1 amp
| ∴ C | = | = 1 amp | ||||
| dt | 2 | dt |
| ⇒ | = 2 V / s | |
| dt |
