The phase angle of the current I with respect to the voltage

The phase angle of the current I with respect to the voltage V₁ in the circuit shown in the figure is

Net voltage applied to the circuit is 200 ∠0° V

I₁ =	200∠0°	= 20∠0° = 20
	10.0

I₂ =	200∠0°	= 20∠90° = -j20
	10∠90°

∴ I = I₁ + I₂ = 20(1 – j) = 20 √2 ∠ 45°
Voltage,V₁ = 100 (1 + j) = 100 √2 ∠ 45°
Required phase angle = – 45° – 45° = – 90°