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Jobs arrive at a facility at an average rate of 5 in an 8 hour shift. The arrival of the jobs follows Poisson distribution. The average service time of a job on the facility is 40 minutes. The service time follows exponential distribution. Idle time (in hours) at the facility per shift will be
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- 5/7
- 14/3
- 7/3
- 10/3
Correct Option: B
Arrival rate = 5 jobs in 8 hr
service time = 40 min/job
∴ Total service time = 40 × 5 = 200 min
| = | = | hrs | ||
| 60 | 3 |
∴ Idle time 1 shift
| = | = | hrs | ||
| 3 | 3 |
