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There are ten animals–two each of lions, panthers, bison, bears, and deer–in a zoo. The enclosures in the zoo are named X, Y, Z, P and Q and each enclosure is allotted to one of the following attendants:
Jack, Mohan, Shalini, Suman and Rita. Two animals of different species are housed in each enclosure. A lion and a deer cannot be together. A panther cannot be with either a deer or a bison. Suman attends to animals from among bison, deer, bear and panther only. Mohan attends to a lion and a panther. Jack does not attend to deer, lion or bison. X, Y, and Z are allotted to Mohan, Jack and Rita respectively. X and Q enclosures have one animal of the same species. Z and P have the same pair of animals. The animals attended by Shalini are:
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- bear and bison
- bison and deer
- bear and lion
- bear and panther
- bear and bison
Correct Option: C
As per the given all information in above question ,
Write down the information given
L → D ( Lion and Dear cannot be together )
P → D & Bs ( A Panther cannot be with a Dear or a Bison )
Suman → L
Mohan → L + P
Jack → P or B
Hence we can short out following table
Since Z & P have the same pair of animals, the other 3 enclosures viz. X, Y and Q must contain the other 3 species within themselves.
So apart from Lion and panther, Bear must be third species in X, Y, Q.
Jack gets Bear and Panther as he doesn't handle lion (given) that leaves. Q with Lion and Bear; which goes to Shalini as Suman doesn't handle lion (given).
