-
then its Fourier transform X(jω) will be—If x(t) = 1000 sin C(1000t) π
-
-
2π rect 
ω 
2000 -
1 π rect 
ω 
2 1000 -
2π rect 
ω 
1000 -
rect 
ω 
2000
-
Correct Option: D
We know that
| x(t) = | ![]() | 0 otherwise |
| then x(jω) = AT.sin C | ![]() | ω | ![]() | 2 |
However, given that

| x(t) = | sin C (100t) | π |
By using duality property
| x(jω)=2πA rect | ![]() | ![]() | t |
The value of a and ω can be calculated as
| = 1000 t | 2 |
or T = 2000
| AT = | π |
| or A = | = | = | ||||
| π·T | π·2000 | 2π |
| Thus, x(jω)=2π· | rect | ![]() | ![]() | |||||
| 2π | 2000 |
| or x(jω) = rect | ![]() | ![]() | 2000 |
Hence, alternative (D) is the correct choice.


