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then its Fourier transform X(jω) will be—If x(t) = 1000 sin C(1000t) π
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2π rect ω 2000 -
1 π rect ω 2 1000 -
2π rect ω 1000 -
rect ω 2000
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Correct Option: D
We know that
x(t) = | ![]() | 0 otherwise |
then x(jω) = AT.sin C | ![]() | ω | ![]() | 2 |
However, given that

x(t) = | sin C (100t) | π |
By using duality property
x(jω)=2πA rect | ![]() | ![]() | t |
The value of a and ω can be calculated as
= 1000 t | 2 |
or T = 2000
AT = | π |
or A = | = | = | ||||
π·T | π·2000 | 2π |
Thus, x(jω)=2π· | rect | ![]() | ![]() | |||||
2π | 2000 |
or x(jω) = rect | ![]() | ![]() | 2000 |
Hence, alternative (D) is the correct choice.