If g(t) = 2 1 + t 2, then G(jω)

We know that

x(t) = e^{– a\|t\|} ↔	2a
	a² + ω²

If a = 1,

then e^{– a\|t\|} ↔	2
	1 + ω²

By using duality property,

	2	↔ 2πe^{– \|– ω\|}
	1 + t²

or	2	↔ 2πe^{– \|ω\|}
	1 + t²

Hence, alternative (A) is the correct choice.