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Signal and systems miscellaneous

Signals and Systems

Direction: for the probability of a Gaussian variable x is given by

Px(x) =
1
e – (x – 4)2/18
3√

Q. (0) = 0·5, Q
4
= 0·09176
3

and Q. (2) = 0·02275

  1. The probability p(x > 0) is—
    1. – 0·90824
    2. 0·90824
    3. 0·09176
    4. – 0·09176
Correct Option: B

P(x > 4) = Q
0 - 4
= Q
– 4
33

= 1 – Q
4
3

= 1 – 0·09176
= 0·90824



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