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Signal and systems miscellaneous

Signals and Systems

Direction: for the probability of a Gaussian variable x is given by

Px(x) =
1
e – (x – 4)2/18
3√

Q. (0) = 0·5, Q
4
= 0·09176
3

and Q. (2) = 0·02275

  1. The probability p(x > – 2) is—
    1. 0·5
    2. 0·97725
    3. 0·90824
    4. None of these
Correct Option: B

P(x > – 2) = Q
x – μx
σx

= Q
– 2 – 4
3

= Q (– 2)
= 1 – Q (2)
= 1 – 0·02275 = 0·97725



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