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Signal and systems miscellaneous

Signals and Systems

Direction: for the probability of a Gaussian variable x is given by

Px(x) =
1
e – (x – 4)2/18
3√

Q. (0) = 0·5, Q
4
= 0·09176
3

and Q. (2) = 0·02275

  1. The probability p(x > 4) is—
    1. 0·5
    2. 0·438
    3. 0·948
    4. 0·843
Correct Option: A

We know that general Gaussion probability density function is given by

Px(x) =
1
e – (x – μx)2/2σ2x
2πσx

On comparing with given equation
Px(x) =
1
e – (x – μx)2/2σ2x
2πσx

μx = 4, σx = 3
P(x > 4) = Q
x – μx
= Q
4 – 4
σx3

= Q(0) = 0·5



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