Principles of Inheritance and Variation Easy Questions and Answers | Page - 41

Principles of Inheritance and Variation

Match the terms in Column-I with their description in Column-II and choose the correct option:

Column-I	Column-II
A.Dominance	1.Many genes govern a single character
B.Codominance	2. In a heterozygous organism only one allele expresses itself
C.Pleiotropy	3. In a heterozygous organism both alleles express themselves fully
D. Polygenic	4.A single gene inheritance influences many characters

1. (ii) (i) (iv) (iii)
1. (ii) (iii) (iv) (i)
1. (iv) (i) (ii) (iii)
1. (iv) (iii) (i) (ii)

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NA

Correct Option: B

NA

A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the F₁ plants were selfed the resulting genotypes were in the ratio of

1. 1: 2: 1:: Tall homozygous: Tall heterozygous: Dwarf
1. 1: 2: 1:: Tall heterozygous: Tall homozygous: Dwarf
1. 3: 1:: Tall: Dwarf
1. 3: 1:: Dwarf: Tall

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Correct Option: A

Which one from those given below is the period for Mendel's hybridization experiments?

1. 1840 - 1850
1. 1857 - 1869
1. 1870 - 1877
1. 1856 - 1863

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According to NCERT, Mendel conducted hybridization experiments for 7 years on Pea plant between 1856 to 1863 and his data was published in 1865.

Correct Option: D

According to NCERT, Mendel conducted hybridization experiments for 7 years on Pea plant between 1856 to 1863 and his data was published in 1865.

Among the following characters, which one was not considered by Mendel in his experiments on pea?

1. Trichomes – Glandular or non-glandular
1. Seed – Green or Yellow → d → d → d
1. Pod – Inflated or Constricted
1. Stem – Tall or Dwarf

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During his experiments Mendel have taken seven characters in a pea plant. In which nature of trichomes i.e., glandular or non-glandular was not considered by Mendel.

Correct Option: A

During his experiments Mendel have taken seven characters in a pea plant. In which nature of trichomes i.e., glandular or non-glandular was not considered by Mendel.

The genotypes of a husband and Wife are I^AI^B and I^Ai. Among the blood types of their children, how many different genotypes and phenotypes are possible?

1. 3 genotypes; 4 phenotypes
1. 4 genotypes; 3 phenotypes
1. 4 genotypes; 4 phenotypes
1. 3 genotypes; 3 phenotypes

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Husband × Wife

Number of genotypes = 4
Number of phenotypes = 3
I^AI^A and I^Ai = A
I^AI^B = AB
I^Bi = B

Correct Option: B

Husband × Wife

Number of genotypes = 4
Number of phenotypes = 3
I^AI^A and I^Ai = A
I^AI^B = AB
I^Bi = B