Thermodynamics Miscellaneous
- A piston-cylinder device initially contains 0.4 m3 of air (to be treated as an ideal gas) at 100 kPa and 80°C. The air is now isothermally compressed to 0.1 m3. The work done during this process is ______kJ.
(Take the sign convention such that work done on the system is negative)
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For isothermal process
W = P1V1ln V2 V1 W = 100 × 0.4 ln 0.1 = -55.45 kJ 0.4 Correct Option: C
For isothermal process
W = P1V1ln V2 V1 W = 100 × 0.4 ln 0.1 = -55.45 kJ 0.4
- The internal energy of an ideal gas is a function of
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temperature only
Correct Option: D
temperature only
- A mixture of ideal gases has the following composition by mass :
N2 O2 CO2 60% 30% 10%
If the universal gas constant is 8314 J/kmolK, the characteristic gas constant of the mixture (in J/kgK) is _______.
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Gas constant of mixture,
Rm = Universal gas constant Average molar mass Rm = Universal gas constant Average molar mass Average molar mass = 100 = 30.233 kg/kmol 60 + 30 + 10 28 32 44 Rm = 8314 = 274.996 J/kg -K 30.233
Correct Option: A
Gas constant of mixture,
Rm = Universal gas constant Average molar mass Rm = Universal gas constant Average molar mass Average molar mass = 100 = 30.233 kg/kmol 60 + 30 + 10 28 32 44 Rm = 8314 = 274.996 J/kg -K 30.233
- For an ideal gas with constant values of specific heats, for calculation of the specific enthalpy,
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it is sufficient to know only the temperature
Correct Option: A
it is sufficient to know only the temperature
- A frictionless piston-cylinder device contains a gas initially at 0.8 MPa and 0.015 m3. It expands quasistatically at constant temperature to a final volume of 0.030 m3. The work output (in kJ) during this process will be
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W = P1V1 ln V2 = 8.317 kJ V1 Correct Option: A
W = P1V1 ln V2 = 8.317 kJ V1