Thermodynamics Miscellaneous


  1. A piston-cylinder device initially contains 0.4 m3 of air (to be treated as an ideal gas) at 100 kPa and 80°C. The air is now isothermally compressed to 0.1 m3. The work done during this process is ______kJ.
    (Take the sign convention such that work done on the system is negative)









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    For isothermal process

    W = P1V1ln
    V2
    V1

    W = 100 × 0.4 ln
    0.1
    = -55.45 kJ
    0.4

    Correct Option: C

    For isothermal process

    W = P1V1ln
    V2
    V1

    W = 100 × 0.4 ln
    0.1
    = -55.45 kJ
    0.4


  1. The internal energy of an ideal gas is a function of









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    temperature only

    Correct Option: D

    temperature only



  1. A mixture of ideal gases has the following composition by mass :
    N2 O2 CO2
    60% 30% 10%

    If the universal gas constant is 8314 J/kmolK, the characteristic gas constant of the mixture (in J/kgK) is _______.









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    Gas constant of mixture,

    Rm =
    Universal gas constant
    Average molar mass

    Rm =
    Universal gas constant
    Average molar mass

    Average molar mass =
    100
    = 30.233 kg/kmol
    60
    +
    30
    +
    10
    283244

    Rm =
    8314
    = 274.996 J/kg -K
    30.233

    Correct Option: A

    Gas constant of mixture,

    Rm =
    Universal gas constant
    Average molar mass

    Rm =
    Universal gas constant
    Average molar mass

    Average molar mass =
    100
    = 30.233 kg/kmol
    60
    +
    30
    +
    10
    283244

    Rm =
    8314
    = 274.996 J/kg -K
    30.233


  1. For an ideal gas with constant values of specific heats, for calculation of the specific enthalpy,









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    it is sufficient to know only the temperature

    Correct Option: A

    it is sufficient to know only the temperature



  1. A frictionless piston-cylinder device contains a gas initially at 0.8 MPa and 0.015 m3. It expands quasistatically at constant temperature to a final volume of 0.030 m3. The work output (in kJ) during this process will be









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    W = P1V1 ln
    V2
    = 8.317 kJ
    V1

    Correct Option: A

    W = P1V1 ln
    V2
    = 8.317 kJ
    V1