Steel structures miscellaneous


Steel structures miscellaneous

  1. For the fillet weld of size ‘s’ shown in the adjoining figure, the effective throat thickness is









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    0.65 s

    Correct Option: B

    0.65 s


  1. Two plates, subjected to direct tension, each of 10 mm thickness and having widths of 100 mm and 175 mm, respectively are to be fillet welded with an overlap of 200 mm. Given that the permissible weld stress is 110 MPa and the permissible stress in steel is 150 MPa, then length of the weld required using the maximum permissible weld size as per IS: 800-1984 is









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    Max. weld size = t – 1.5 = 10 – 1.5 = 8.5
    Max. strength of plate = t × b × ft
    = 10 × 100 × 150 = 150 kN

    ∴ 150 =
    1
    × 5 × l × 110
    2

    ∴ l = 226.91 mm

    Correct Option: B

    Max. weld size = t – 1.5 = 10 – 1.5 = 8.5
    Max. strength of plate = t × b × ft
    = 10 × 100 × 150 = 150 kN

    ∴ 150 =
    1
    × 5 × l × 110
    2

    ∴ l = 226.91 mm



  1. A double cover butt riveted joint is used to connect two flat plates of 200 mm width and 14 mm thickness as shown in the figure (on the next page). There are twelve power driven rivets of 20 mm diameter at a pitch of 50 mm in both directions on either side of the plate. Two cover plates of 10 mm thickness are used. The capacity of the joint in tension considering bearing and shear ONLY, with permissible bearing and shear stresses as 300 MPa respectively is









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    Strength of rivets in shear (double)

    = 12 × 2 ×
    π
    × (20 + 1.5)2 × 100
    4

    = 871.32 kN
    Strength of rivets of bearing,
    = 12 × (20 + 1.5) × 14 × 300 = 1083.6 kN
    ∴ The minimum = 871.32 kN

    Correct Option: B

    Strength of rivets in shear (double)

    = 12 × 2 ×
    π
    × (20 + 1.5)2 × 100
    4

    = 871.32 kN
    Strength of rivets of bearing,
    = 12 × (20 + 1.5) × 14 × 300 = 1083.6 kN
    ∴ The minimum = 871.32 kN


  1. A 12 mm thick plate is connected to two 8 mm plates, on either side through a 16 mm diameter power driven field rivet as shown in the figure below. Assuming permissible shear stress as 90 MPa and permissible bearing stress as 270 MPa in the rivet, the rivet value of the joint is









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    Shear failure (double)

    = 2 ×
    π
    × (16 + 1.5)2 × 90
    4

    = 43.295 kN
    Bearing failure = 12 × (16 + 1.5) × 270 = 56.7 kN
    ∴ Rivet value = minimum of two = 43.295 kN

    Correct Option: B

    Shear failure (double)

    = 2 ×
    π
    × (16 + 1.5)2 × 90
    4

    = 43.295 kN
    Bearing failure = 12 × (16 + 1.5) × 270 = 56.7 kN
    ∴ Rivet value = minimum of two = 43.295 kN



  1. The degree of static indeterminacy of a rigidly jointed frame in a horizontal plane and subjected to vertical loads only, as shown in figure below is









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    Static indeterminacy = 6 – 3 = 3

    Correct Option: C

    Static indeterminacy = 6 – 3 = 3