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A 12 mm thick plate is connected to two 8 mm plates, on either side through a 16 mm diameter power driven field rivet as shown in the figure below. Assuming permissible shear stress as 90 MPa and permissible bearing stress as 270 MPa in the rivet, the rivet value of the joint is
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- 56.70 kN
- 43.29 kN
- 36.19 kN
- 21.65 kN
Correct Option: B
Shear failure (double)
| = 2 × | × (16 + 1.5)2 × 90 | 4 |
= 43.295 kN
Bearing failure = 12 × (16 + 1.5) × 270 = 56.7 kN
∴ Rivet value = minimum of two = 43.295 kN
