Steel structures miscellaneous


Steel structures miscellaneous

  1. A steel strip of length, L = 200 mm is fixed at end A and rests at B on a vertical spring of stiffness, k = 2 N/mm. The steel strip is 5 mm wide and 10 mm thick. A vertical load, P = 50 N is applied at B, as shown in the figure. Considering E = 200 GPa, the force (in N) developed in the spring is____________









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    K =
    F
    δ

    K =
    R
    δ

    ⇒ δ =
    R
    K

    For cantilever,
    δ =
    (p - R)L3
    =
    R
    3EIk


    ⇒ R = 3N

    Correct Option: A


    K =
    F
    δ

    K =
    R
    δ

    ⇒ δ =
    R
    K

    For cantilever,
    δ =
    (p - R)L3
    =
    R
    3EIk


    ⇒ R = 3N


  1. A bracket plate connected to a column flange transmits a load of 100 kN as shown in the following figure. The maximum force for which the bolts should be designed is _____ kN.









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    FD =
    P
    =
    100
    = 20 kN
    n5


    Ft =
    (P.d)r
    Σ r2

    =
    100 × 600 × 75√2
    = 141.42 kN
    4 × (75√2)2


    400 + 19999.616 + 3999.96
    = 156.204 kN

    Correct Option: C

    FD =
    P
    =
    100
    = 20 kN
    n5


    Ft =
    (P.d)r
    Σ r2

    =
    100 × 600 × 75√2
    = 141.42 kN
    4 × (75√2)2


    400 + 19999.616 + 3999.96
    = 156.204 kN



  1. A symmetric I-section (with width of each flange = 50 mm, thickness of each flange = 10 mm, depth of web = 100 mm and thickness of web = 10 mm) of steel is subjected to a shear force of 100 kN. Find the magnitude of the shear stress (in N/mm2) in the web at its junction with the top flange.









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    I =
    50 × 1203
    -
    40 × 1003
    1212

    = 3.866 × 106 mm4
    q =
    SAy
    =
    100 × 103 × 50 × 10 × 55
    Ib3.866 × 106 × 10

    = 71.12 N/mm2

    Correct Option: A


    I =
    50 × 1203
    -
    40 × 1003
    1212

    = 3.866 × 106 mm4
    q =
    SAy
    =
    100 × 103 × 50 × 10 × 55
    Ib3.866 × 106 × 10

    = 71.12 N/mm2


  1. The tension and shear force (both in kN) in each bolt of the joint, as shown below, respectively are









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    Horizontal component = Pu cos θ
    Tension in each bolt,

    Pu cos θ
    6

    =
    250 × 4
    = 33.3 kN
    5 × 6

    Shear in each bolt = Vertical component
    =
    3 × 250
    = 25 kN
    5 × 6

    Correct Option: D


    Horizontal component = Pu cos θ
    Tension in each bolt,

    Pu cos θ
    6

    =
    250 × 4
    = 33.3 kN
    5 × 6

    Shear in each bolt = Vertical component
    =
    3 × 250
    = 25 kN
    5 × 6



  1. A steel section is subjected to a combination of shear and bending actions. The applied shear force is V and the shear capacity of the section is Vs. For such a section, high shear force (as per IS:800-2007) is defined as









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    As per IS 800:2007
    V > 0.6 Vs

    Correct Option: A

    As per IS 800:2007
    V > 0.6 Vs