Steel structures miscellaneous
- A steel strip of length, L = 200 mm is fixed at end A and rests at B on a vertical spring of stiffness, k = 2 N/mm. The steel strip is 5 mm wide and 10 mm thick. A vertical load, P = 50 N is applied at B, as shown in the figure. Considering E = 200 GPa, the force (in N) developed in the spring is____________
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K = F δ K = R δ ⇒ δ = R K
For cantilever,δ = (p - R)L3 = R 3EI k
⇒ R = 3NCorrect Option: A
K = F δ K = R δ ⇒ δ = R K
For cantilever,δ = (p - R)L3 = R 3EI k
⇒ R = 3N
- A bracket plate connected to a column flange transmits a load of 100 kN as shown in the following figure. The maximum force for which the bolts should be designed is _____ kN.
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FD = P = 100 = 20 kN n 5 Ft = (P.d)r Σ r2 = 100 × 600 × 75√2 = 141.42 kN 4 × (75√2)2
√400 + 19999.616 + 3999.96
= 156.204 kNCorrect Option: C
FD = P = 100 = 20 kN n 5 Ft = (P.d)r Σ r2 = 100 × 600 × 75√2 = 141.42 kN 4 × (75√2)2
√400 + 19999.616 + 3999.96
= 156.204 kN
- A symmetric I-section (with width of each flange = 50 mm, thickness of each flange = 10 mm, depth of web = 100 mm and thickness of web = 10 mm) of steel is subjected to a shear force of 100 kN. Find the magnitude of the shear stress (in N/mm2) in the web at its junction with the top flange.
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I = 50 × 1203 - 40 × 1003 12 12
= 3.866 × 106 mm4q = SAy = 100 × 103 × 50 × 10 × 55 Ib 3.866 × 106 × 10
= 71.12 N/mm2Correct Option: A
I = 50 × 1203 - 40 × 1003 12 12
= 3.866 × 106 mm4q = SAy = 100 × 103 × 50 × 10 × 55 Ib 3.866 × 106 × 10
= 71.12 N/mm2
- The tension and shear force (both in kN) in each bolt of the joint, as shown below, respectively are
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Horizontal component = Pu cos θ
Tension in each bolt,Pu cos θ 6 = 250 × 4 = 33.3 kN 5 × 6
Shear in each bolt = Vertical component= 3 × 250 = 25 kN 5 × 6 Correct Option: D
Horizontal component = Pu cos θ
Tension in each bolt,Pu cos θ 6 = 250 × 4 = 33.3 kN 5 × 6
Shear in each bolt = Vertical component= 3 × 250 = 25 kN 5 × 6
- A steel section is subjected to a combination of shear and bending actions. The applied shear force is V and the shear capacity of the section is Vs. For such a section, high shear force (as per IS:800-2007) is defined as
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As per IS 800:2007
V > 0.6 VsCorrect Option: A
As per IS 800:2007
V > 0.6 Vs