Soil mechanics miscellaneous

Soil mechanics miscellaneous

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Soil Mechanics

Soil mechanics miscellaneous
  1. The avoid ratios at the densest, loosest and the natural states of a sand deposit are 0.2, 0.6 and 0.4, respectively, the relative density of the deposit is








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    ID =
    emax - e
    		× 100
    emax - emin

    =
    0.6 - 0.4
    		× 100
    0.6 - 0.2

    =
    0.2
    		× 100 = 50%
    0.4

    Correct Option: C

    ID =
    emax - e
    		× 100
    emax - emin

    =
    0.6 - 0.4
    		× 100
    0.6 - 0.2

    =
    0.2
    		× 100 = 50%
    0.4

  1. Data from a sieve analysis conducted on a given sample of soil showed that 67% of the particles passed through 75 micron IS sieve. The liquid limit and plastic limit of the finer fraction was found to be 45 and 33 percents respectively. The group symbol of the given soil as per IS:1498-1970 is








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    Since more than 50% n of sample pass through 75µ sieve, it is fine grained soil.
    wL = 45%
    Q WL > 35% and < 50%, it is intermediate compressible
    (I) Equation of A-line
    Ip = 0.73 (WL – 20)
    = 0.73 (45 – 20) = 18.25%
    ∴ Ip is below A line,
    ∴ it is silty soil (m)
    ∴ Group symbol is MI

    Correct Option: B

    Since more than 50% n of sample pass through 75µ sieve, it is fine grained soil.
    wL = 45%
    Q WL > 35% and < 50%, it is intermediate compressible
    (I) Equation of A-line
    Ip = 0.73 (WL – 20)
    = 0.73 (45 – 20) = 18.25%
    ∴ Ip is below A line,
    ∴ it is silty soil (m)
    ∴ Group symbol is MI

  1. The coefficients of permeability of a soil in horizontal and vertical directions are 3.46 and 1.5 m/day respectively. The base length of a concrete dam resting in this soil is 100 m. When the flow net is developed for this soil with 1:25 scale factor in the vertical direction, the reduced base length of the dam will be








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    kx = 3.46 m/d
    ky = 1.5 m/d

    = 65.84 m
    Apply scale factor of 1: 25

    65.84
    		= 2.63 m
    25

    Correct Option: A

    kx = 3.46 m/d
    ky = 1.5 m/d

    = 65.84 m
    Apply scale factor of 1: 25

    65.84
    		= 2.63 m
    25

  1. A deep cut of 7 m has to be made in a clay with unit weight 16 kN/m3 and a cohesion of 25 kN/m2. What will be the factor of safety if one has to have a slope angle of 30°? Stability number is given to be 0.178 (from Taylor’s chart) for a depth factor of 3.








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    Sn =
    C
    Fc.γH

    0.178 =
    25
    Fc.16 × 7

    ⇒ Fc = 1.25

    Correct Option: C

    Sn =
    C
    Fc.γH

    0.178 =
    25
    Fc.16 × 7

    ⇒ Fc = 1.25

  1. A borrow pit soil has a dry density of 17 kN/m3. How many cubic meters of this soil will be required to construct an embankment of 100 m3 volume with a dry density of 16 kN/ m3








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    Borrow pit volume be v1
    Embankment volume bc V2 = 100 m3

    V1
    		=
    γd2
    V2γd1

    ⇒
    V1
    		=
    16
    10017

    ⇒ V1 = 94.11 m3

    Correct Option: A

    Borrow pit volume be v1
    Embankment volume bc V2 = 100 m3

    V1
    		=
    γd2
    V2γd1

    ⇒
    V1
    		=
    16
    10017

    ⇒ V1 = 94.11 m3