Oscillations


Physics of Sound

  1. The composition of two simple harmonic motions of equal periods at right angle to each other and with a phase difference of π results in the displacement of the particle along​









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    x = a sin ωt ​
    and y = b sin (ωt + π) = – b sin ωt

    or
    x
    = -
    y
    or y = -
    b
    x
    aba

    It is an equation of a straight line.

    Correct Option: C

    x = a sin ωt ​
    and y = b sin (ωt + π) = – b sin ωt

    or
    x
    = -
    y
    or y = -
    b
    x
    aba

    It is an equation of a straight line.


  1. The potential energy of a long spring when  stretched by 2 cm is U. If the spring is stretched by 8 cm, the potential energy stored in it is









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    The potential energy of a spring =
    1
    kx2
    2

    U =
    1
    k.(2)2 = 4 ×
    1
    k
    22

    For x = 8 cm, ​
    Energy stored =
    1
    k.(8)2 = 64 ×
    1
    k
    22

    = 64 ×
    U
    = 16 U
    4

    Correct Option: B

    The potential energy of a spring =
    1
    kx2
    2

    U =
    1
    k.(2)2 = 4 ×
    1
    k
    22

    For x = 8 cm, ​
    Energy stored =
    1
    k.(8)2 = 64 ×
    1
    k
    22

    = 64 ×
    U
    = 16 U
    4



  1. The particle executing simple harmonic motion has a kinetic energy K0 cos2 ω t. The maximum values of the potential energy and the total energy are respectively









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    We have, U + K = E ​
    where, U = potential energy, K = Kinetic energy, E = Total energy. ​
    Also, we know that, in S.H.M., when potential energy is maximum, K.E. is zero and vice-versa. ​ ​
    ∴ Umax - 0 = E ⇒ Umax = E
    Further,

    K.E. =
    1
    2 a2 cos2 ωt
    2

    But by question , K.E. = K0 cos2 ωt
    K0 =
    1
    2 a2
    2

    Hence, total energy, E =
    1
    2 a2 = K0
    2

    ∴ Umax = K0 & E = K0

    Correct Option: C

    We have, U + K = E ​
    where, U = potential energy, K = Kinetic energy, E = Total energy. ​
    Also, we know that, in S.H.M., when potential energy is maximum, K.E. is zero and vice-versa. ​ ​
    ∴ Umax - 0 = E ⇒ Umax = E
    Further,

    K.E. =
    1
    2 a2 cos2 ωt
    2

    But by question , K.E. = K0 cos2 ωt
    K0 =
    1
    2 a2
    2

    Hence, total energy, E =
    1
    2 a2 = K0
    2

    ∴ Umax = K0 & E = K0


  1. A particle moving along the X-axis, executes simple harmonic motion then the force acting on it is given by​​









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    For simple harmonic motion, F = – Kx. ​
    Here,  K = Ak.

    Correct Option: A

    For simple harmonic motion, F = – Kx. ​
    Here,  K = Ak.



  1. Which one of the following is a simple harmonic motion ?​​









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    A wave moving through a string fixed at both ends, is a transverse wave formed as a result of simple harmonic motion of particles of the string.

    Correct Option: C

    A wave moving through a string fixed at both ends, is a transverse wave formed as a result of simple harmonic motion of particles of the string.