The particle executing simple harmonic motion has a kinetic

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The particle executing simple harmonic motion has a kinetic energy K₀ cos² ω t. The maximum values of the potential energy and the total energy are respectively

1. K₀ / 2 and K₀
2. K₀ and 2K₀
3. K₀ and K₀
4. 0 and 2K₀.

Correct Option: C

We have, U + K = E
where, U = potential energy, K = Kinetic energy, E = Total energy.
Also, we know that, in S.H.M., when potential energy is maximum, K.E. is zero and vice-versa.
∴ U_max - 0 = E ⇒ U_max = E
Further,

K.E. =	1	mω² a² cos² ωt
	2

But by question , K.E. = K₀ cos² ωt

K₀ =	1	mω² a²
	2

Hence, total energy, E =	1	mω² a² = K₀
	2

∴ U_max = K₀ & E = K₀