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The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm, the potential energy stored in it is
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- 8 U
- 16 U
- U / 4
- 4 U
Correct Option: B
The potential energy of a spring = | kx2 | |
2 |
U = | k.(2)2 = 4 × | k | ||
2 | 2 |
For x = 8 cm,
Energy stored = | k.(8)2 = 64 × | k | ||
2 | 2 |
= 64 × | = 16 U | |
4 |