Home » Physics of Sound » Oscillations » Question

Physics of Sound

  1. The potential energy of a long spring when  stretched by 2 cm is U. If the spring is stretched by 8 cm, the potential energy stored in it is
    1. ​8 U
    2. 16 U
    3. U / 4
    4. 4 U
Correct Option: B

The potential energy of a spring =
1
kx2
2

U =
1
k.(2)2 = 4 ×
1
k
22

For x = 8 cm, ​
Energy stored =
1
k.(8)2 = 64 ×
1
k
22

= 64 ×
U
= 16 U
4



Your comments will be displayed only after manual approval.