Ray Optics and Optical Instruments
- The radius of curvature of a thin plano-convex lens is 10 cm (of curved surface) and the refractive index is 1.5. If the plane surface is silvered, then it behaves like a concave mirror of focal length
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The silvered plano convex lens behaves as a concave mirror ; whose focal length is given by
1 = 2 + 1 F f1 fm
If plane surface is silveredfm = R2 = ∞ = ∞ 2 2 ∴ 1 = (μ - 1) 1 - 1 f1 R1 R2 = (μ - 1) 1 - 1 = μ - 1 R ∞ R ∴ 1 = 2(μ - 1) + 1 = 2(μ - 1) F R ∞ R F = R 2(μ - 1)
Here, R = 10 cm, µ = 1.5∴ F = 10 = 10 cm 2(1.5 - 1) Correct Option: A
The silvered plano convex lens behaves as a concave mirror ; whose focal length is given by
1 = 2 + 1 F f1 fm
If plane surface is silveredfm = R2 = ∞ = ∞ 2 2 ∴ 1 = (μ - 1) 1 - 1 f1 R1 R2 = (μ - 1) 1 - 1 = μ - 1 R ∞ R ∴ 1 = 2(μ - 1) + 1 = 2(μ - 1) F R ∞ R F = R 2(μ - 1)
Here, R = 10 cm, µ = 1.5∴ F = 10 = 10 cm 2(1.5 - 1)
- A body is located on a wall. Its image of equal size is to be obtained on a parallel wall with the help of a convex lens. The lens is placed at a distance 'd' ahead of second wall, then the required focal length will be
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Using the lens formula , 1 = 1 - 1 f v u
Given v = d, for equal size image | v | = | u | = d
By sign convention u = –d∴ 1 = 1 + 1 or f = d f d d 2
Correct Option: B
Using the lens formula , 1 = 1 - 1 f v u
Given v = d, for equal size image | v | = | u | = d
By sign convention u = –d∴ 1 = 1 + 1 or f = d f d d 2
- A convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens. Then its focal length will
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1 = (ℓμg - 1) 1 - 1 f R1 R2
where , ℓμg = 1 is given⇒ 1 = (1 - 1) 1 - 1 = 0 ⇒ f = ∞ f R1 R2 Correct Option: C
1 = (ℓμg - 1) 1 - 1 f R1 R2
where , ℓμg = 1 is given⇒ 1 = (1 - 1) 1 - 1 = 0 ⇒ f = ∞ f R1 R2
- An equiconvex lens is cut into two halves along (i) XOX' and (ii) YOY' as shown in the figure. Let f, f ', f '' be the focal lengths of the complete lens, of each half in case (i), and of each half in case (ii), respectively.
Choose the correct statement from the following
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1 = (μ - 1) 1 - 1 f R1 R2
In this case, R1 and R2 are unchanged
So, f will remain unchanged for both pieces of the lens
∴ f = f '1 = 1 + 1 f f1 f2
This is combination of two lenses of equal focal lengths∴ 1 = 1 + 1 = 2 ⇒ f" = 2f f f" f" f" Correct Option: B
1 = (μ - 1) 1 - 1 f R1 R2
In this case, R1 and R2 are unchanged
So, f will remain unchanged for both pieces of the lens
∴ f = f '1 = 1 + 1 f f1 f2
This is combination of two lenses of equal focal lengths∴ 1 = 1 + 1 = 2 ⇒ f" = 2f f f" f" f"
- A convex lens and a concave lens, each having same focal length of 25 cm, are put in contact to form a combination of lenses. The power in diopters of the combination is
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From the formula,
1 = 1 + 1 = 1 - 1 = 0 f f1 f2 25 25 Power of combination = 1 = 0 f Correct Option: C
From the formula,
1 = 1 + 1 = 1 - 1 = 0 f f1 f2 25 25 Power of combination = 1 = 0 f