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An equiconvex lens is cut into two halves along (i) XOX' and (ii) YOY' as shown in the figure. Let f, f ', f '' be the focal lengths of the complete lens, of each half in case (i), and of each half in case (ii), respectively.
Choose the correct statement from the following
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- f ' = 2f, f '' = 2f
- f ' = f, f '' = 2f
- f ' = 2f, f '' = f
- f ' = f, f '' = f
Correct Option: B
= (μ - 1) | ![]() | - | ![]() | ||||
f | R1 | R2 |
In this case, R1 and R2 are unchanged
So, f will remain unchanged for both pieces of the lens
∴ f = f '

= | + | ||||
f | f1 | f2 |
This is combination of two lenses of equal focal lengths
∴ | = | + | = | ⇒ f" = 2f | ||||
f | f" | f" | f" |