Network theory miscellaneous


  1. The time constant for the given circuit will be—











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    The given circuit:

    The equivalent circuit for calculating time constant is shown below:

    Now, time constant,

    τ = Req Ceq = 6 ×
    2
    = 4sec
    3

    Hence alternative (C) is the correct choice.

    Correct Option: C

    The given circuit:

    The equivalent circuit for calculating time constant is shown below:

    Now, time constant,

    τ = Req Ceq = 6 ×
    2
    = 4sec
    3

    Hence alternative (C) is the correct choice.


  1. The voltage V for the network shown below is—











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    The given network:

    The voltage V for the above network is always equal to 10V.

    Correct Option: A

    The given network:

    The voltage V for the above network is always equal to 10V.



  1. The circuit shown in the figure above—











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    The given circuit:

    Applying KVL in the input side, we get
    V1 + 3I1 + I1R + (I1 + I2) R = 0
    or
    V1 = I1 (2R – 3) + I2R . . .. .…(i)
    Again applying KVL in the output side
    V2 = I2R + (I1 + I2)R
    or
    V2 = I1R + I2.2R …. . . . .(ii)
    From equation (i) and (ii)
    Z11 = 2R – 3, Z12 = R
    Z21 = R, Z22 = 2R
    ● For the network to be symmetric
    Z11 = Z22 (But here Z11 = 2R – 3 and Z22 = 2R)
    So, network is not symmetric.
    ● For the network to be reciprocal:
    Z12 = Z21 (Here Z12 = Z21 = R)
    So, network is reciprocal.
    Thus, we conclude that the given network is reciprocal but not symmetric.

    Correct Option: A

    The given circuit:

    Applying KVL in the input side, we get
    V1 + 3I1 + I1R + (I1 + I2) R = 0
    or
    V1 = I1 (2R – 3) + I2R . . .. .…(i)
    Again applying KVL in the output side
    V2 = I2R + (I1 + I2)R
    or
    V2 = I1R + I2.2R …. . . . .(ii)
    From equation (i) and (ii)
    Z11 = 2R – 3, Z12 = R
    Z21 = R, Z22 = 2R
    ● For the network to be symmetric
    Z11 = Z22 (But here Z11 = 2R – 3 and Z22 = 2R)
    So, network is not symmetric.
    ● For the network to be reciprocal:
    Z12 = Z21 (Here Z12 = Z21 = R)
    So, network is reciprocal.
    Thus, we conclude that the given network is reciprocal but not symmetric.


  1. The phasor combination of resistive power and reactive power is called—









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    The phasor combination of resistive power and reactive power is called apparent power.

    Correct Option: B

    The phasor combination of resistive power and reactive power is called apparent power.



  1. Norton’s current in the circuit shown below is—











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    The given circuit

    From figure
    2iN – 5iN = 0
    or
    iN = 0A

    Correct Option: B

    The given circuit

    From figure
    2iN – 5iN = 0
    or
    iN = 0A