In the circuit shown in the figure, if the current in resistance

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In the circuit shown in the figure, if the current in resistance R is Nil, then

1. ωL₁ = 1
  R₁ ωC₄R₄
2. ωL₁ = ωC₄R₄
  R₁
3. tan^-1 ωL₁ + tan^-1 ωC₄R₄ = 0
  R₁
4. tan^-1 ωL₁ + tan^-1 1 = 0
  R₁ ωC₄R₄

Correct Option: A

From the circuit,

	R_i + jωL₁	=	R₂
	R₃			R₄ -	j
					ωC₄

⇒ (R_l + jωL₁)		R₄ -	1		= R₂R₃
			ωC₄

Equating imaginary part, we have

	ωL₁	=	10
	R₁		ωC₄R₄