The circuit shown in Fig. (a) replaced by its Norton’s

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The circuit shown in Fig. (a) replaced by its Norton’s equivalent in Fig. (b) The value of will be

1. 2.5 ∠ 45° A
2. 5 ∠ 90° A
3. 10 ∠– 90° A
4. 15 ∠– 45° A

Correct Option: A

I =	25
	5 - j10 + j5

=	25	= 2.5 ∠ 45° A
	5 - 5j