Thevenin equivalent of the network shown in Fig. (a) is

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Thevenin equivalent of the network shown in Fig. (a) is 10 V in series with a resistance of 2 Ω. If a resistance of 3 Ω is connected across AB as shown in Fig. (b), then Thevenin equivalent of the modified network across AB will be

1. 10 V in series with 1.2 Ω resistance
2. 6 V in series with 1.2 Ω resistance
3. 10 V in series with 5 Ω resistance
4. 6 V in series with 5 Ω resistance

Correct Option: B

R_eq =	2 × 3	= 1.2 Ω
	2 + 3

V_oc =	10 × 3	= 6 V
	3 + 2